The AnswerUnderstanding Kirchhoff's Laws and Sign Conventions for RL Circuits

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Kirchhoff's laws for RL circuits involve understanding the signs of potential differences across components. In a circuit with a resistor and an inductor, the loop rule requires that the sum of potential differences equals zero, with one being positive and the other negative. The equation -L(dI/dt) - iR = 0 is derived by considering the direction of current flow; if traveling with the current, the inductor's back emf is positive and the resistor's voltage drop is negative. Conversely, if the direction is reversed, both terms can be expressed positively, leading to the same relationship. Understanding these sign conventions is crucial for correctly applying Kirchhoff's laws in circuit analysis.
cherev
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about kirchoff?

Homework Statement



can anybody explain why we write kirchhoff laws on RL circuit like

-Ldı/dt -iR=0

shouldn't it be written like

-Ldı/dt +iR=0



Homework Equations



-Ldı/dt -iR=0
-Ldı/dt +iR=0



it is about signs and how we know inductans' poles + or - while writing these equations
 
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maybe the inductor can be considered as a normal resisitor...therefore its written as -iR
 
Hi cherev,

From your equation, I guess your RL circuit is just a resistor and an inductor attached together (no voltage source).

In that case, Kirchoff's loop rule indicates that the magnitudes of the potential differences must be the same for the resistor and inductor, and that one must be positive and one must be negative. (That's the only way two potential differences would cancel as you travel around the loop.) Which one is positive and which one is negative depends on whether you go clockwise or counterclockwise around the loop.

So let's say we travel around the loop in the same direction as the current. Then the potential difference across the resistor is negative, and across the inductor is positive:

<br /> {V}_L -I R =0<br />

But V_L is the back emf of the inductor, and is therefore V_L = -L (dI/dt), giving your result.

If you go the other way around the loop, V_R=IR is positive and V_L is negative, which leads to the same result except with both terms positive.
 
thanks...!
 
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