The Attempt at a SolutionReduce Ellipse: Centre & Eccentricity

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    Ellipse Reduction
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The discussion focuses on reducing the given ellipse equation to standard form and determining its center and eccentricity. By substituting X and Y into the equation, it simplifies to a more manageable format. The center of the ellipse is identified at the coordinates (-1, -2). The eccentricity can be derived from the standard form of the ellipse equation. This method is praised for its simplicity and effectiveness in solving the problem.
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Homework Statement


Reduce the given ellipse in standard form and find its centre and eccentricity.

4(x-2y+1)2 + 9(2x+y+2)2 = 25

Homework Equations



Rotation of axes
x=Xcosθ - Ysinθ
y=Xsinθ + Ycosθ
 
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I would not use the "rotation of axes" formulas. Instead, let X= x- 2y and Y= 2x+ y so that your equation becomes
\frac{4}{25}(X- (-1))^2+ \frac{9}{25}(Y- (-2))^2= 1

What is the center and eccentricity of that ellipse? Now go back to x and y coordinates.
 
Wow! that is a very nice method. Thanks!
 
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