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**The average f(x) value, from a mechanical point of view? Algebra I and II method?**

I don't quite understand why the average point value of the function x

^{2}is x

^{2}/3 from a mechanical point of view -> no integrals, I also don't prefer derivative approach.

For example:

* tilt your head to the right to see the graphs in standard orientation or even better alt ctrl left

k=y

J=J

the average is k because everything is k=====y====

==lllllllllllllllllllllllll

==lllllllllllllllllllllllll

x=llllllllllllllllllllllllll

==lllllllllllllllllllllllll

==lllllllllllllllllllllllll

kx=y

the average is kx/2

=====y====

==llll

==llllllll

x=llllllllllll

==llllllllllllllll

==llllllllllllllllllll

kx

^{2}= y

the average is kx

^{2}/3

=====y======

==ll

==llll

x=llllllll

==lllllllll

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