The cost to transmit the energy to the city each hour is $534.944.

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SUMMARY

The energy plant produces an output potential of 4100 kV and transmits energy to a city located 121 km away using a high-voltage transmission line carrying 1530 A. The effective resistance of the transmission line is calculated at 2.05 Ω/km, resulting in a potential provided to the city of 3720.484 kV. Power dissipation due to resistive losses is determined to be 5.8 x 10^8 W. The cost to transmit energy, based on a rate of $0.093 per kW/hr, is confirmed to be $534.944 per hour after correcting for unit conversion errors.

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AdnamaLeigh
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A) An energy plant produces an output potential of 4100 kV and serves a city 121 km away. A high-voltage transmission line carries 1530 A to the city. The effective resistance of a transmission line [wire(s)] is 2.05 Ω/km times the distance from the plant to the city. What is the potential provided to the city, i.e., at the end of the transmission line?

Answer: 3720.484 kV

B) How much power is dissipated due to resistive losses in the transmission line?

Answer: 5.8 x 10^8 W

C) Assume the plant charges $0.093 / kW x hr for electric energy. At this rate, how much does it cost to transmit the energy to the city (by the transmission line heating the atmosphere) each hour? Answer in units of dollars/hr.

This is the one I'm stuck on. I thought that I was supposed to mutliply 5.8 x 10^5 kW with $.093 but then I get $54001 per hour and that just does not seem reasonable.
 
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This:
AdnamaLeigh said:
Answer: 5.8 x 10^8 W
And this:
AdnamaLeigh said:
Answer: 5.8 x 10^8 kW
Are not the same. If your original number is correct, you are a factor of 10^{-3} out, which would make your answer $54.001

-Hoot:smile:
 
I don't quite understand what you mean. I know that those two numbers are not the same. When I changed it to kW, I subtracted 3 powers from the exponent.

Either way, $54.001 isn't the answer, I checked and it failed.
 

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