The earth takes exactly 24 hours for one full rotation calculate

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The discussion focuses on calculating the speed of rotation at the equator, which is approximately 465 m/s. The formula used is speed = 2πr/T, where r is the Earth's radius and T is the time for one full rotation (24 hours). Participants emphasize the importance of using the correct radius of Earth, approximately 6.378 x 10^6 meters, to derive the circumference and subsequently the speed. There is a clarification on the calculation method, highlighting the need to use parentheses when dividing by the total seconds in a day to avoid errors. Accurate calculations and rounding can lead to slight variations in results, but the key takeaway is the correct application of the formula with proper values.
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the speed of rotation of a point on the equator

the title is the only information I have been given to work out this questions and it relates to a2 phyics uniform circular motion and the answer is 465ms-1 I just cannot get it I know the eqautor must have something to do with it PLEASE HELP

Full calculations shown please!

the textbook gives equations speed = 2pi*r/T but I am not given radius and using the radius does not give the correct answer anyway

the closest I got was 471 ms-1 using pi/24*3600 and I just used pi because I am assuming because it asks along the equ I should use 180 degrees
 
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If you're getting 471, it could just be a matter of how you're rounding some of the variables like pi or the radius of the Earth.

I used the exact same equation using the pi option on my calculator and for r, I used 6.378x10^6 and I got 463.82m/s.

Hope this helps!
 
The Earth takes 24 hours to make a full rotation with respect to the Sun. The Earth is also orbiting the Sun. This means it takes a bit less than 24 hours for that Earth to make a full rotation with respect to the stars. Another way to look at it is that the Earth rotates a bit more than 360 degrees in 24 hours. This extra little bit of rotation is what gives that answer of 465.1 m/s as opposed to the 463.8 m/s that gbaby370 obtained.
 
sazzy said:
the speed of rotation of a point on the equator

the title is the only information I have been given to work out this questions and it relates to a2 physics uniform circular motion and the answer is 465ms-1 I just cannot get it I know the equator must have something to do with it PLEASE HELP

Full calculations shown please!

the textbook gives equations speed = 2pi*r/T but I am not given radius and using the radius does not give the correct answer anyway

the closest I got was 471 ms-1 using pi/24*3600 and I just used pi because I am assuming because it asks along the equ I should use 180 degrees

Hello sazzy. Welcome to PF.

Look up the radius of Earth.

Using that, you can find circumference of Earth, which is the distance that a point on the equator travels in one day.

The number of seconds in one day is 24*3600.

If you want to divide some number by 24*3600, you should put (24*3600) in parentheses.

When you computed π/24*3600, that was equivalent to 3600*π/24 . It's just a coincidence that this gave a result that's close to the correct answer.
 
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