- #1
matai
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So I found the linear velocity by using the circumference of the Earth which I found to be 2pi(637800= 40014155.89meters. Then the time of one full rotation was 1436.97 minutes, which I then converted to 86164.2 seconds. giving me the linear velocity to be 465.0905584 meters/second. I know that this is the orbital motion and I need the rotational
I found an old forum saying to use use density * Δvolume for mass, and the linear velocity with the formula KE=½mv^2. Then, integrate over the volume of the earth, i found that to be 108.321 × 10^10 km^3. So, my integral was something like this:
∫(½(465.0905584)^2(5514)dv
a=0, b=108.321 × 10^10
I ended up with 6.46005E20. I don' think is right for some reason.
I tried again with the integral:
∫(½(465.0905584)^2(5514*v)dv
a=0, b=108.321 × 10^10
and got 3.49878E32. I'm not sure if either one is right.
I found an old forum saying to use use density * Δvolume for mass, and the linear velocity with the formula KE=½mv^2. Then, integrate over the volume of the earth, i found that to be 108.321 × 10^10 km^3. So, my integral was something like this:
∫(½(465.0905584)^2(5514)dv
a=0, b=108.321 × 10^10
I ended up with 6.46005E20. I don' think is right for some reason.
I tried again with the integral:
∫(½(465.0905584)^2(5514*v)dv
a=0, b=108.321 × 10^10
and got 3.49878E32. I'm not sure if either one is right.
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