The equation for any set of lines passing through an ellipse with the same slope

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Homework Help Overview

The discussion revolves around proving that the equation y = mx ± √(a²m² + b²) represents two lines that are tangent to an ellipse defined by (x/a)² + (y/b)² = 1. The participants are exploring the relationship between the lines and the ellipse, particularly focusing on the conditions under which the lines touch the ellipse at a single point.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of the equation provided, questioning whether the lines are indeed tangent to the ellipse or if they simply pass through it. There is an exploration of how to demonstrate that the lines intersect the ellipse at a single point, with suggestions to use the quadratic formula to analyze the roots of the resulting equation.

Discussion Status

The conversation is active, with participants raising questions about the clarity of the problem statement and the mathematical reasoning involved. Some guidance has been offered regarding the use of the quadratic formula to identify conditions for tangency, but no consensus has been reached on the interpretation of the problem.

Contextual Notes

There is a noted confusion regarding the terminology used in the problem statement, particularly the distinction between lines that pass through the ellipse and those that are tangent to it. Participants are also grappling with the implications of the mathematical setup and the necessary conditions for tangency.

VonWeber
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Homework Statement



I was tutoring a student and could not answer one of his questions. Prove that y = mx +- square root( a^2*m^2 + b^2 ) is the equation for two lines passing through an ellipse

Homework Equations



(x/a)^2 + (y/b)^2 = 1 is the equation of an ellipse

The Attempt at a Solution



I started by suggesting he implicitly differentiate the equation for an ellipse and put it in the point slope equation, but it turned out to give an equation for dy/dx = m, but not the desired equation. I worked on different approaches at home for half an hour, but I'm stumped.
 
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Passing through an ellipse? As in they're tangent to it?
 
This is a bit confusing. You title this "the equation for any set of lines passing through an ellipse with the same slope" but then give an equation for exactly two lines.

Look at [itex]y = mx + \sqrt{ a^2*m^2 + b^2 }[/itex] and [itex]y = mx - \sqrt{ a^2*m^2 + b^2 }[/itex] separately. Where do they cross the ellipse [itex](x/a)^2 + (y/b)^2 = 1[/itex]? I think, like genneth, that it is quite possible they intend these to be the two lines that are tangent to the ellipse on opposite sides.
 
Yeah, of course I meant tangent. don't be so nitpicky
 
There's the boring and tedious way, which is to show that the lines intercept the ellipse at a single point -- substitute one into the other, show that the ensuing quadratic has a single repeated root. There's probably some other clever geometrical proof.
 
VonWeber said:
Yeah, of course I meant tangent. don't be so nitpicky
Don't be so nitpicky? You leave out a crucial part of the problem, mis-state another part and you consider that nitpicky? And you are a mathematics tutor?
 
So I take for one part: y² = (mx)² + 2mx√(a²m² + b²) + a²m² + b²
substituting for y² in the equations for an ellipse I get:

x²(1/a² + m/b²) + x[2m√(a²m² + b²)/b²] + a²m² = 0

I don't see how to make it clear that this has a repeated root, and I'm unclear on why that means it is a tangent to the ellipse.
 
Well, when does the equation [tex]ax^2 + bx + c = 0[/tex] have a repeated root? Chuck it into the quadratic formula and see if you can't spot something obvious.
 

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