The Fundamental Theorem of Calculus

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Homework Help Overview

The discussion revolves around the Fundamental Theorem of Calculus, focusing on the relationship between integration and differentiation. The original poster expresses confusion regarding the geometric interpretation of a 1-D curve as the derivative of an area function, seeking a more intuitive understanding of this concept.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the connection between integration and differentiation, with one suggesting that the concept of "primitives" may clarify the relationship. Others mention resources like videos to aid understanding, while the original poster indicates that existing resources have not fully addressed their concerns.

Discussion Status

The discussion is ongoing, with participants sharing insights and resources. There is an acknowledgment of the complexity of the topic, and while some guidance has been offered, there is no explicit consensus on the original poster's confusion.

Contextual Notes

The original poster notes a struggle with visualizing the geometric interpretation of area functions in relation to derivatives, indicating a potential gap in understanding that is being explored through various suggestions and clarifications.

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Homework Statement


I'm having trouble wrapping my head around this concept. I understand integration and differentiation individually. I even understand the algebraic manipulations that reveals their close relationship. However, the typical geometric interpretation of a 1-D curve being the derivative of the area function below it seems odd to me. I'm trying to get an intuitive understanding of how a 1-D curve, say A'(x) = f(x) , is the derivative of an area function, A(x). I think I might know where my source of confusion lays: When dealing with derivatives, I'm used to visualizing in terms of tangent lines drawn to a 1-D curve. It seems weird to apply it to an area function, which is more irregular polygon than it is 1-D curve. I hope my concerns make sense.

Homework Equations

The Attempt at a Solution

 
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Googling doesn't help ?
 
try googling

mit Session 47: Introduction of the Fundamental Theorem of Calculus

and watch that
 
+ S[x+dx] = S[x] + f(x)dx. Obvious from geometry. => f(x)=S'(x)
 
William White said:
try googling

mit Session 47: Introduction of the Fundamental Theorem of Calculus

and watch that
Great video, but it didn't quite answer my question. I might not have been able to articulate my question that well over the internet. Oh, well. Thanks, anyhow.
 
I think the missing link between integration and differentiation is primitiv(-isation,-ization, -ation, ..., I don't know). It is the 'reciprocal' operation to differentiation: ##\phi## is a primitive of a piecewise continuous fonction ##f## if and only if ##\phi## is differentiable on the domain of ##f## and ##\phi' = f##.
The set of all primitives of ##f## vary by an additive constant. So all primitives of ##f## have the form ##\phi = \phi_0 + C##, where ##\phi_0## is a particular primitive of ##f##.
It happens that the function ##\phi_0(x) :=\int_{x_0}^x f(t) dt ## is a primitive of ##f## wherever ##f## is continuous (just show that if ## f## is continuous in ##a##, ## \frac{\phi_0(x) - \phi_0(a)}{x-a} \rightarrow f(a) ## as ## x\rightarrow a## ). I think it explains a little bit the link between integration and differentiation.The link between the area under the curve of ##f##, defined on ##[a,b]##, and its integral, comes from the construction of the integral of piecewise continuous functions from the integral of step-functions on ##[a,b]##, which are homogenous to an area
 

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