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The Horizontal Distance

  1. Oct 17, 2006 #1
    hi guys.. could you please explain why 2.0x10^1 meters is the answer of the horizontal distance between the log and the bridge when the stone is dropped from rest from a 75-m-high bridge and lands on the log as it passess under the bridge if the log moves with a constant speed of 50 meters per second?
     
  2. jcsd
  3. Oct 17, 2006 #2
    Are you sure the answer is 20 meters? Its either ur answer is wrong or that the log is travellin at a speed too fast in water!
     
    Last edited: Oct 17, 2006
  4. Oct 17, 2006 #3

    radou

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    Doesn't sound right. From the equation of the displacement of the stone [tex]y = 75 - \frac{1}{2}gt^2[/tex] you can obtain the time it takes to fall down, by setting y equal to zero and solving for t. Further on, use that time to obtain the distance of the log at the moment just before the stone is dropped.
     
  5. Oct 17, 2006 #4
    well. The answer should be approximately 200 if the values given are correct. Or else, there may be some error in the question.
     
  6. Oct 17, 2006 #5

    radou

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    Yes, it's near 200 [m].
     
  7. Oct 17, 2006 #6
    the log is travelling 50 meters per second.. yeah i think its 200 meters..ok.. i got it.. thanks guys...
     
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