The least constant acceleration

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To determine the least constant acceleration required for a large plane to reach a takeoff speed of 360 km/h on a 1.8 km runway, the kinematic equation v^2 = u^2 + 2as can be used. The initial speed (u) is 0, the final speed (v) is 360 km/h, and the distance (s) is 1.8 km. Rearranging the equation allows for the calculation of acceleration (a). The discussion highlights confusion regarding the correct application of the formula and the need to find the time taken to reach the speed. Understanding these concepts is essential for solving the problem accurately.
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OK, here's the problem:
A large plane needs to get to a speed of 360 km/h on it's runway in order to take off. The runway is 1.8 km long. What would be the least constant acceleration required to take off?

Physics just started, I need shock paddles to get me going again

Thanks
 
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Please show your own work. You must at least have some idea as to what equations to use?
 
Would it have to have a constant acceleration of 200 km/h to reach it's top speed by the end of the runway, or am I missing something? :cry:
 
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Well, I divided 360 km/h by the distance, 1.8 km, and got 200. Is that the least constant acceleration needed to take off? I'm very confused.
 
So I think the next thing I need to do is figure out the time it takes to reach that speed along that distance. So what was this 200 I was getting? 200 km/h?

I have the speed, I have the distance, how do I find the time it took to do this, or am I going off course?
 
try

v^2 = u^2 +2as

and rearrange for acceleration, a.
 
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