What is the equation for determining the magnitude of a vector in 2D space?

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SUMMARY

The equation for determining the magnitude of a vector in 2D space is derived from the components of the vector, specifically using the horizontal component \(u_1\) and the vertical component \(u_2\). The correct formulation is \(u = u_1 \cos{\theta} + u_2 \sin{\theta}\), where \(\theta\) is the angle with respect to the horizontal. This equation does not directly yield the magnitude of a single vector but rather provides the components in a specific direction. The fundamental relationship is established through the Pythagorean theorem, confirming that \(u = u \cos^2{\theta} + u \sin^2{\theta}\) simplifies back to \(u\).

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CivilSigma
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Homework Statement


For any vector in 2D space, it can be broken down into its horizontal and vertical components.

Homework Equations


In one of my engineering classes, we are using the following equation to determine the magnitude of a vector:

$$u=v_1 \cdot cos\theta +u_2 \cdot sin\theta$$

Where $\theta$ is the angle with respect to the horizontal, v1 is the horizontal component and v2 is the vertical component of the vector.

I know this equation works but I don't understand why.
I feel like I am missing a fundamental concept, because to determine the magnitude of a vector, I would use Pythagoras theorem, and I cannot derive the above equation from Pythagoras's equation.

The Attempt at a Solution

 
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Can you provide some context for where this equation is applied? Perhaps give a specific example.

In general, this equation will not work for a single vector whose x and y components are ##u_1## and ##u_2##. Perhaps they are summing the horizontal components of two different vectors to obtain a net horizontal resultant?
 
That equation doesn't give the magnitude of the vector. It gives you the component of the vector in the direction of ##\hat n = \cos\theta\,\hat i + \sin\theta\,\hat j##.
 
CivilSigma said:
In one of my engineering classes, we are using the following equation to determine the magnitude of a vector:
u=v1⋅cosθ + u2⋅sinθ​

Where $\theta$ is the angle with respect to the horizontal, v1 is the horizontal component and v2 is the vertical component of the vector.

I know this equation works but I don't understand why.

It comes from geometry... See this diagram... If that's not clear do say and I will explain some more.

Magnitude of Vector.png
 

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I think you meant to write the equation as $$u=u_1\cos{\theta}+u_2\sin{\theta}\tag{1}$$where $$u_1=u\cos{\theta}\tag{2}$$and$$u_2=u\sin{\theta}\tag{3}$$If you substitute Eqns. 2 and 3 into Eqn. 1, you get:
$$u=u\cos^2{\theta}+u\sin^2{\theta}=u$$
 
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