The mesh current method - Am I doing it right?

Click For Summary

Discussion Overview

The discussion revolves around the application of the mesh current method to solve a circuit problem, specifically to find the current I0. Participants explore the setup of mesh currents, the impact of current sources, and the interactions between different meshes in the circuit.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The initial setup involves defining mesh currents I1 and I2 for different parts of the circuit, with I0 expressed as I0=I1-I2.
  • One participant claims I1 is -5 due to the direction of the current source, and calculates I2 as (-22.5)/7.
  • Another participant suggests checking the direction of mesh currents and emphasizes the need to account for interactions between meshes, particularly the shared components affecting potential changes.
  • The suggestion to use the supermesh method is made to better capture the relationships between the meshes, especially where a current source is involved.
  • A later reply indicates that the supermesh was successfully set up, resulting in a total of three meshes being considered, including the two bottom meshes and one supermesh for the top circuit.

Areas of Agreement / Disagreement

Participants express differing views on the initial setup and calculations, particularly regarding the direction of mesh currents and the need for additional equations to account for interactions. The discussion remains unresolved as participants refine their approaches without reaching a consensus.

Contextual Notes

Limitations include potential assumptions about current directions and the interactions between meshes that may not be fully articulated. The discussion reflects varying interpretations of the mesh current method and its application to the specific circuit problem.

foxofdesert
Messages
21
Reaction score
0

Homework Statement


Apply the mesh current method to find I0


Homework Equations


Mesh current method


The Attempt at a Solution



On the left bottom square circuit, I set a mesh current, I1, and on the right bottom square circuit, I set a mesh current, I2.

Then, I0=I1-I2.

Since there is a current source on the mesh I1, I1=-5 (negative sign because of the direction.)
and
(1+2+4)I2+22.5=0, so I2=(-22.5)/7.
Therefore, I0=-5-(-22.5)/7=(-12.5)/7.

Am I doing it right?
 

Attachments

  • hw.jpg
    hw.jpg
    20.8 KB · Views: 536
Physics news on Phys.org
Please check the attachment to see the problem.
 
foxofdesert said:
On the left bottom square circuit, I set a mesh current, I1, and on the right bottom square circuit, I set a mesh current, I2.

Then, I0=I1-I2.
Okay.
Since there is a current source on the mesh I1, I1=-5 (negative sign because of the direction.)
and
(1+2+4)I2+22.5=0, so I2=(-22.5)/7.
Therefore, I0=-5-(-22.5)/7=(-12.5)/7.
Check your mesh current direction; the potential changes across the resistors in the second mesh should drop in the direction of mesh current flow.

Also, you need to take into account the effect of the other currents in the circuit. In particular, the mesh current in the top right mesh also passes through the 2Ω resistor shared with the bottom right mesh. Similarly, the top left mesh affects conditions in the top right mesh (in general, all the meshes interact due to shared components).

You'll have to write equations relating all the meshes in order to capture the interactions. For the bottom left mesh you can take its current as given (-5A) since it's constrained by a current source there. For the top pair, you might want to employ the supermesh method to write the two equations that describe it.
 
Thanks for your help.

I set up the super mesh on the top since they share a current source, so I set up total of 3 mesh ( 1 supermesh, 2 mesh for each bottom circuit) and solved the problem.

Thank you so much
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K