The Mystery: Solving a Brain Teaser with Water and Weight

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The brain teaser involves determining the weight needed on one side of a see-saw to push a 1 cubic meter styrofoam cube 1 meter up in a 10-meter tall water column. The setup assumes no friction and a seal preventing water from escaping. A participant points out that if the seal is frictionless, the styrofoam would act as a piston, lifting the entire water column instead of being pushed down. The discussion emphasizes that the water level remains constant despite the movement of the styrofoam. The challenge lies in calculating the necessary force to achieve this movement under the given conditions.
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a little brain teaser..:))

hi ...i'm having a hard time figuring out this one. see attachment pic. a water coluumn, square based tube ( 1 x 1 meters ) - height 10 meters. what will be the amount for the red weight at one side of the see-saw in order to push a styrofoam cube sized( 1x1x1meters=1 cubic meter) . the force must be sufficient to push the styrofoam inside the water column 1 meter up (so it will be at 9 meters depth).
theoretically there is no friction, and there is a seal blocking the water from flowing down and out of the pipe.

ideas?
thanks
 

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alibaba2 said:
the force must be sufficient to push the styrofoam inside the water column 1 meter up (so it will be at 9 meters depth).
theoretically there is no friction, and there is a seal blocking the water from flowing down and out of the pipe.

I don't get this one: If there is a frictionless seal between the styrofoam and the cylinder, then you can't push the foam "into" the water; the foam will act like a piston and you'll simply lift the entire column
 


ok, forget the frictionless seal detail, what i mena is there is no loss of water...i.e. all water leaked out below is compensated above, so water level remains constant.
thanks
 
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