Engineering The operation of magnetically coupled circuits

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A transformer with 600 primary turns and 150 secondary turns has primary and secondary resistances of 0.25Ω and 0.01Ω, and reactances of 1.0Ω and 0.04Ω, respectively. The equivalent resistance and reactance referred to the primary winding were calculated as 0.41Ω and 1.64Ω, but the turns ratio should be squared in these calculations. The discussion highlights that if there is no load on the secondary, the secondary circuit can be ignored, simplifying the analysis to just the primary winding. Some participants suggest that the problem may lack context or necessary load characteristics, leading to confusion about the relevance of the provided information. Ultimately, clarity on the problem's context is essential for accurate resolution.
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Homework Statement



A transformer has 600 primary turns and 150 secondary turns. The primary and the second resistances are 0.25Ω and 0.01 Ω respectively and the corresponding reactances are 1.0Ω and 0.04Ω respectively.
Detemine the equivalent:
1. resistance
2. the reactance and
3. the equivalent impedance reffered to the primary winding
4. the phase angle of the impedance.

Anyone could help me with this question? Thank you

Homework Equations





The Attempt at a Solution

 
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I have been trying to answer some of them myself.
For equivalent resistance:
2
Re= R1 + R2= R1 + R2 ( V1 : V2)

Re= 0.41Ω

For equivalent reactance:
2
Xe= X1 + X2' = X1 + X2 ( V1: V2)

Xe= 1.64 Ω

Am i correct?
 
Is there a load on the secondary? If not, just ignore the secondary winding altogether and solve the circuit with the primary winding only.
 
Thanks. I will solve it OK now
 
The problem may be referring to the transformer equivalent model referred to the primary. If so, the results reported by Agata78 in post #2 look correct (although the math as presented is not correct as the turns ratio should be squared in both cases).
 
gneill said:
The problem may be referring to the transformer equivalent model referred to the primary. If so, the results reported by Agata78 in post #2 look correct (although the math as presented is not correct as the turns ratio should be squared in both cases).

If there is no load there is no secondary circuit. There is only a single inductor. The model, turns ratio, secondary leakage inductance and resistance do not matter.
 
rude man said:
If there is no load there is no secondary circuit. There is only a single inductor. The model, turns ratio, secondary leakage inductance and resistance do not matter.

The problem may be referring to the model alone and not a complete circuit. Or, if you like, consider the secondary to be shorted. The OP would have to put the problem in context to clarify (is the problem associated with a chapter covering the transformer model, for example). Otherwise it's hard to see the point of providing the all the information that's given.
 
gneill said:
The problem may be referring to the model alone and not a complete circuit. Or, if you like, consider the secondary to be shorted. The OP would have to put the problem in context to clarify (is the problem associated with a chapter covering the transformer model, for example). Otherwise it's hard to see the point of providing the all the information that's given.

You can't short the secondary without toxic smoke! This is a power xfmr; look at the primary and secondary winding impedances. The components in the model referring to the secondary winding may be totally removed without affecting the four things asked for in the problem if there is no load.

My suspicion is that either the OP left out load characteristics, or it's a trick question. Probably the former.
 

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