- #1
dE_logics
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The P.D of a charged capacitor should be more than the charging source...
That's cause the charge felt by the cell on its terminals might be less that the net charge (depends on what level of charging is the capacitor in), as a result charge accumulation continues until the plates are saturated with charge and it finally gets exposed to the terminals of the battery. After this level of saturation, we can be ensured that the P.D by virtue of the net charge stored in each plate will be more than that of the charging source's. That's cause, there much of the charge on the plates which are being mutually held by each other and cannot be felt by the terminals of the charging source.
If the plates are dismantled at this stage, the potential difference gained by the individual pates will be equal and having more potential than the charging source (cause now the net charge can be exposed and felt).
That's cause the charge felt by the cell on its terminals might be less that the net charge (depends on what level of charging is the capacitor in), as a result charge accumulation continues until the plates are saturated with charge and it finally gets exposed to the terminals of the battery. After this level of saturation, we can be ensured that the P.D by virtue of the net charge stored in each plate will be more than that of the charging source's. That's cause, there much of the charge on the plates which are being mutually held by each other and cannot be felt by the terminals of the charging source.
If the plates are dismantled at this stage, the potential difference gained by the individual pates will be equal and having more potential than the charging source (cause now the net charge can be exposed and felt).