The physical meaning of Schrödinger's equation

kahoomann
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OK, I understand the physical interpretation of wave function which is the solution of Schrödinger's equation. The interpretation of wave function is in term of probability.
What is physical meaning of Schrödinger's equation itself, in term of Newton's equation(F=ma)?
 
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Check out this thread, in particular post #8.

Hey, you're the one who asked the question then. :confused:
 
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You could perhaps see Schrodinger equation as the quantistical equivalent of Newton's law in the sense that while Newton's law tells you the "future story" of a non-quantistical particle (its trajectory due to forces), the Schrodinger equation tells you the same for a quantistical particle. The difference being that for a quantistical particle you cannot speak of a trajectory in the classical sense due to the Heisenberg uncertainty principle, but you can speak of a wave function (with a probabilistic meaning) and Schrodinger equation will tell you the "future story" of the wave function.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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