The potential difference necessary to accelerate an He+ ion ?

AI Thread Summary
To accelerate a He+ ion (charge +e, mass 4u) from rest to a speed of 1.2×10^6 m/s, the necessary potential difference can be calculated using the relationship between kinetic energy and electric potential. The kinetic energy gained by the ion is equal to the product of its charge and the potential difference (ΔKE = q*ΔV). The charge of the He+ ion is 1.6×10^-19 coulombs, and the relevant equations for kinetic energy and potential difference are discussed. The user expresses confusion about the problem and seeks clarification on the units of potential difference, confirming that volts are indeed the correct units. The discussion concludes with the user gaining understanding of the relationship between electric potential and kinetic energy.
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The potential difference necessary to accelerate an He+ ion...?

Homework Statement



"What potential difference is needed to accelerate a He+ ion (charge +e, mass 4u) from rest to a speed of 1.2×10^6 m/s?"

Homework Equations



K_f + q*V_f = K_i + q*V_i

The Attempt at a Solution



I figure that:

q = 1.6*10^-19 for the charge of an electron I believe...?

I started off thinking these were somehow true:

V_f = (1/2) m*vf^2

V_i = (1/2) m*vi^2

but now I realize that's just silly, and they both equal K...which is the kinetic energy, sure...but I still have *no* idea what the V's are going to be!

I'm honestly kind of banging my head against the book here...it's not really teaching me what I need to do this problem in any reasonably understandable way. Can anyone help out with this?
 
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What are the units of (electrical) potential difference? Volts, right? But the Volt is a "compound" unit comprising [Joules]/[Coulomb].

So a charge q accelerating though potential difference V will acquire kinetic energy qV:

ΔKE = q*ΔV
 


You're absolutely right :D Got it, ty!
 
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