The pressure sand exerts on a particular area.

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The discussion focuses on calculating the pressure exerted by falling sand grains on a surface, using the formula P=F/A. Each sand grain has a mass of 3.0x10^-3 g and falls from a height of 0.8 m at a rate of 50 grains per second per cm^2. Participants debate whether to treat the sand particles as an ideal gas and discuss the appropriate area to use in SI units. The conversation emphasizes the need to apply the full form of the force equation, F=ma, and consider the rate of change of momentum. Ultimately, the goal is to determine the pressure resulting from the impact of the sand on the surface.
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Grains of sand of mass 3.0x10^-3 g each, fall from a height of 0.8 m on a sticky surface at a rate of 50 grains per second per cm^2. What pressure does this shower of sand exert on the surface, assuming that air resistance can be neglected?

I'm really not sure what angle to take here. I believe they are trying to get me to use the equation P=F/A, however, F=ma? and F/A=mv^2(N/V).

Am I suppose to treat this problem like an ideal gas, because the sand particles are so light?

In addition, should i use 0.0001 m^2 for the area since it is SI units?
 
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Hi Physics321! :smile:

Use the full form of F = ma … F = d/dt (mv) …

how much mv is changing per second? :wink:
 

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