The proof of Time Scaling, Laplace transform

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The discussion focuses on the proof of time scaling using the Laplace transform, specifically addressing the transformation of the integral in equation 6.96. The key steps involve manipulating the exponential term by introducing a constant factor 'a' and changing the variable of integration from 't' to 't'' using the substitution t' = at. This results in a simplified integral form that retains the properties of the original function while adjusting for the scaling factor.

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killahammad
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Hi

I understand most of the steps in the determination of the time scale. But i don't really understand the step in equation 6.96.

The first attachment is the full details of the time scale, and the second attachment is the part which I am stuck on.

I just want to know, how they get from the LHS to the RHS of the equation

Thanks for any help :)
 

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Last edited:
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to go from
[tex]\int_0^\infty e^{-st}f(at)dt[/tex]
You do 2 things: Multiply -st in the exponential by a/a= 1 and rewrite (st)(a/a)= (s/a)(at); also write (a/a)dt= (1/a)(adt). Since a is a constant, we can take the 1/a outside the integral and write adt= d(at). That gives you
[tex]\frac{1}{a}\int_0^\infty e^{-\frac{s}{a}}(at)f(at)d(at)[/tex]
Now, put in a new variable: let t'= at. Then dt'= d(at). When t= 0, u= t' and, as t goes to infinity, t' goes to infinity. In the variable t', f(at)= f(t') so we have
[tex]\frac{1}{a}\int_0^\infty e^{(s/a)t'} f(t)dt'[/tex]
 
thank you very much, that helped me a lot
 

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