The relation between span(In,A,A2, )and it's minimal polynomial

alazhumizhu
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Let A ∈ Mn×n(F )
Why dim span(In, A, A2, A3, . . .) = deg(mA)?? where mA is the minimal polynomial of A.
For span (In,A,A2...)

I can prove its

dimension <= n by CH Theorem

but what's the relation between

dim span(In,A,A2...)and deg(mA)
 
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For example, if the minimal polynomial is x^2+x+1. Then A^2+A+1=0.

Do you see any way to conclude that A^2\in span(A,1)?
 
ybut i don't know why can't I write A
 
ybut i don't know why can't I write A in spanA2I
 
y,but i don't know why can't I write A in span{A2,I}?
I'm sorry about the type..
 
alazhumizhu said:
y,but i don't know why can't I write A in span{A2,I}?
I'm sorry about the type..

That's also true, but I don't see how this fact helps you solve the problem.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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