The Relation of Pressure to Molecular Energy

AI Thread Summary
Molecules in a liquid escape when they gain enough energy to overcome attractive forces, leading to vaporization. Boiling occurs when vapor pressure equals atmospheric pressure, allowing all molecules to escape. The relationship between pressure and molecular energy is complex, as pressure is defined as thrust per unit area. Increasing the temperature of a liquid raises its vapor pressure by adding energy, facilitating the escape of molecules. Understanding this interplay between pressure and molecular energy is crucial in thermodynamics.
miss photon
Messages
23
Reaction score
0
when some molecules in a liquid gain enough energy to overcome attractive forces by surrounding molecules, they escape from the liquid surface. but when the vapor pressure becomes equal to atmospheric pressure, boiling is said to take place and all the molecules seem to gain sufficient energy to escape. what is the relation of pressure with 'energy' of the molecules? after all pressure is only thrust per unit area. how can it affect the energy of the molecules?
 
Physics news on Phys.org
You increase the vapor pressure by raising the temperature of the liquid (by adding energy to it).
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top