- #1

Edge5

- 22

- 0

kT = (1/2)mv^2

which gives v=√((2kT)/m)

but answer says it should be √((kT)/m)

Where did that 2 go?

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- Thread starter Edge5
- Start date

- #1

Edge5

- 22

- 0

kT = (1/2)mv^2

which gives v=√((2kT)/m)

but answer says it should be √((kT)/m)

Where did that 2 go?

- #2

- 13,288

- 1,709

kT = (1/2)mv^2

which gives v=√((2kT)/m)

but answer says it should be √((kT)/m)

Where did that 2 go?

By the equipartition theorem, there is a factor of 1/2 kT for each kinetic degree of freedom. Assume the electrons moves only in one direction as a classical point particle. You then get the sqrt formula without the 2 in it.

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