The weak force and effective coupling

ian2012
Messages
77
Reaction score
0
I just read something about the creation of deuteron in the first step of the pp cycle. Given that you have the reaction: p + p -> d + e^+ + v_e, where e^+ is a positron and v_e is an electron neutrino. Since there is a neutrino present, it is a weak interaction. In addition, as the interaction is weak (and at low energies?) the effective coupling is small.

My question is, do weak interactions only proceed at low energies? I have read about 'low energy limits' and how this means only virtual W's can be made. How is it then that this process can proceed at roughly 1.5 x 10^7 K in the Sun's core?
 
Physics news on Phys.org
Weak interactions in generally occur most readily at energies where the intermediate gauge boson is very close to its mass shell (about 80 GeV for the W and 90 GeV for the Z). However, at that kind of energy the nucleons involved tend to fragment, so you wouldn't get deuterium.

Also, not that 1.5 x 10^7 K does not get you to terribly high energy. It only amounts to an avererage of 1.3 keV kinetic energy per proton, which is, as these things go, rather low energy. (Remember, the electron's mass is 511 keV and the proton's is 938 MeV.)
 
Okay then, so weak interactions don't really proceed at low energies? (i am not too sure what the ideal energies are for strong interactions).
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top