There is a magnetic friction force in a dynamo?

AI Thread Summary
In a rotating dynamo, the interaction between the magnetic field and the coil can create a phenomenon akin to "magnetic friction force," which may decelerate the rotating magnet. This effect can occur even in a vacuum, where there is no mechanical contact or air resistance. Such magnetic friction is recognized in various applications, including power tools, where it serves as a safety feature to quickly stop motors. Understanding this force is essential for optimizing the performance and safety of electric devices. The existence of magnetic friction force in dynamos is well-established in physics.
DanteBR
Messages
9
Reaction score
0
There is a "magnetic friction force" in a dynamo?

In a rotating dynamo, where the magnet rotates surrounded by a coil, there is something like a "magnetic friction force"? The magnetic field causes an effect similar to mechanical friction, that can slow down the revolving magnet?
 
Physics news on Phys.org


Does anyone know if such a thing exist?

Imagine that the dynamo is in a vacuum chamber. The rotating magnet does not touch the coil, and there is no air, so there is no aerodynamic drag.

So, I wonder if there is something like a "magnetic friction force", decelerating the rotating magnet. There is this?
 


DanteBR said:
So, I wonder if there is something like a "magnetic friction force", decelerating the rotating magnet. There is this?
Yes, it is well known. Some power tools employ the effect to stop motors quickly. It's a safety feature in for example power saws and electric lawnmowers.
 
Thread 'Inducing EMF Through a Coil: Understanding Flux'
Thank you for reading my post. I can understand why a change in magnetic flux through a conducting surface would induce an emf, but how does this work when inducing an emf through a coil? How does the flux through the empty space between the wires have an effect on the electrons in the wire itself? In the image below is a coil with a magnetic field going through the space between the wires but not necessarily through the wires themselves. Thank you.
I was using the Smith chart to determine the input impedance of a transmission line that has a reflection from the load. One can do this if one knows the characteristic impedance Zo, the degree of mismatch of the load ZL and the length of the transmission line in wavelengths. However, my question is: Consider the input impedance of a wave which appears back at the source after reflection from the load and has traveled for some fraction of a wavelength. The impedance of this wave as it...
Back
Top