A 3.8 kg block of copper at a temperature of 72C is dropped into a bucket containing a mixture of ice and water whose total mass is 1.2 kg. when thermal equilibrium is reached, the temperature of the water is 8C. How much ice was in the bucket before the copper block was placed in it? (Neglect heat capacity of the bucket).(adsbygoogle = window.adsbygoogle || []).push({});

Heat gained=heat lost

Mice(Lf)+(Mwater)(Cwater)(Teq-Ti)=(Mcopper)(Ccopper)(Ti-Teq)

then i tried to solve for the mass of the ice, but the Ti of water is also unknown so I could not solve it. Also, it said to ignore the heat capacity of the bucket,so i left it out of the equation completely.

Thanks for any help!!

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Thermal equilibrium with water and ice

**Physics Forums | Science Articles, Homework Help, Discussion**