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butters120
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Homework Statement
Two brass plates, each 0.5 cm thick, have a rubber spacer sheet between them, which is 0.1 cm thick. The outer side of one brass plate is kept at 0 oC, while the outer side of the other is at 100 oC. Find the temperature of the two sides of rubber spacer if the thermal conductivity of brass is approximately 500 times higher than that of rubber.
Homework Equations
I have Q/t=KA[dT/dx] and Q/t=A(Th-Tc)/sum of (Li/Ki) where Ki=thermal conductivity of each material and Li= thickness of material.
The Attempt at a Solution
I have tried setting the Q/t=A(Th-Tc)/sum of (Li/Ki) equal to each other for each brass sheet, like i had split the spacer sheet up, but i don't think this is right. other than that i do not know where to go from the equation. Please help :(