Thermal Properties: Pressure, Volume, Temp question

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Homework Help Overview

The problem involves a Jaguar XK8 convertible's engine cylinder, focusing on the thermal properties of air during the compression stroke. The initial conditions include a specific volume, pressure, and temperature, while the final conditions include a reduced volume and increased gauge pressure. The objective is to determine the final temperature of the air in the cylinder.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the ideal gas law and the need to convert temperature to Kelvin. There is uncertainty about the appropriateness of the equation used for the calculation and whether it can yield the final temperature directly. Some participants suggest considering isentropic processes and the relationships between pressure, volume, and temperature.

Discussion Status

Several participants have provided hints and alternative approaches, including the suggestion to use isentropic relationships and the ideal gas law. There is ongoing exploration of the correct method to find the final temperature, with no consensus reached on the best approach yet.

Contextual Notes

Participants note that the problem may involve assumptions about the process being isentropic and that the use of specific constants for air may be necessary. There is also a mention of the requirement to express the final temperature in Celsius, which could influence the calculations.

wcbryant87
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Homework Statement



A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499 cm cubed of air at atmospheric pressure (1.01E5 Pa) and a temperature of 27.0 degrees C. At the end of the stroke, the air has been compressed to a volume of 46.2 cm cubed and the gauge pressure has increased to 2.72E6.

What is the final temperature

Homework Equations



P1*V1/T1 = P2*V2/T2



The Attempt at a Solution



I followed the equation that I posted above. Here is what it looked like.

(1.01E5 * 499 cm cubed)/ 27 = (2.72E6 * 46.2)/x

Solving for x, I got x = (2.72E6*46.2)/1866629.63 = 66.8 degrees C

Problem is, that answer is apparently wrong. Am I missing something here?

Thanks for the help!
 
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Try changing your temperature to kelvin :)
 
well it wants the answer in celsius. Does that equation have to be done with Kelvin units?
 
Were you given that equation? As you won't find T2 like that. Even if you use kelvin as the pv/pv is a ratio, it won't make any difference.

Hint: Expansion and compression is isentropic.
 
No I wasn't given any equation. I thought that that one would work though because I was only missing one variable.

Do I use pv=nrt?
 
If you've got a book, look up isentropic compression.

pv^gamma = constant.

where gamma is the polytropic constant you'll have to find the relationship between temperature and anther variable.
 
xxChrisxx said:
If you've got a book, look up isentropic compression.

pv^gamma = constant.

where gamma is the polytropic constant you'll have to find the relationship between temperature and anther variable.
Thats the Adiabatic process.

Calculate the mass of air in the cylinder from pv=mRT

Constants for air Cp=1005J/kgK, Cv=718J/kgK R=287J/kgK, calculate gamma from these.

Reaarange the equation for an adiabatic process to find T
 
its both acutally, as isentropic is adiabatic and reversible. to find the temperatre after compression you don't need the mass in the cylinder as it comes out in the wash.

the relationships for isentropic processes for ideal gases are listed in any thermo textbook. but as this is homework help I am not going to just give them out.
 
Last edited:

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