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1. The problem statement, all variables and given/known data

A 50-g chunk of 80 degree C iron is dropped into a cavity in a very large block of ice at 0 degrees C. How many grams of ice will melt? (The specific heat capacity of iron is .11 cal/g*C)

2. Relevant equations

Q = cmdeltaT

Quantity of heat = heat capacity * mass * change in temp

also i know that it takes 80 calories to go just from ice to water

3. The attempt at a solution

All my attempts have met with failure:

1) .11cal/g*C * 50g(x-80C)=.5*y(x-0C) (i dont know the mass of ice so im clueless on how to solve this)

2) .11cal/g*c *50g(0-80C)=.5*y(0-0C) (assuming that the ice will equalize the final temp but it leaves the right equation = 0 which makes it pointless.

There is a re-occurring number that I keep having and its 440 cal/g. Any and all help is appreciated.

I figured it out, my second equation was correct. Thanks though!

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# Homework Help: Thermo Energy. Iron + Ice

Can you offer guidance or do you also need help?

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