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Thermo Energy. Iron + Ice

  1. Feb 19, 2008 #1
    [SOLVED] Thermo Energy. Iron + Ice

    1. The problem statement, all variables and given/known data
    A 50-g chunk of 80 degree C iron is dropped into a cavity in a very large block of ice at 0 degrees C. How many grams of ice will melt? (The specific heat capacity of iron is .11 cal/g*C)


    2. Relevant equations
    Q = cmdeltaT
    Quantity of heat = heat capacity * mass * change in temp

    also i know that it takes 80 calories to go just from ice to water

    3. The attempt at a solution
    All my attempts have met with failure:

    1) .11cal/g*C * 50g(x-80C)=.5*y(x-0C) (i dont know the mass of ice so im clueless on how to solve this)

    2) .11cal/g*c *50g(0-80C)=.5*y(0-0C) (assuming that the ice will equalize the final temp but it leaves the right equation = 0 which makes it pointless.

    There is a re-occurring number that I keep having and its 440 cal/g. Any and all help is appreciated.

    I figured it out, my second equation was correct. Thanks though!
     
    Last edited: Feb 19, 2008
  2. jcsd
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