Thermo Exam Question: Estimate Temp & Pressure After Compression

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The discussion focuses on estimating temperature and pressure after isentropic compression in a spark ignition engine. For pure air, the charge compresses from 1 bar to 7 bar with a temperature increase calculated using isentropic relations. When considering a stoichiometric mixture of air and octane, the specific heats vary, requiring adjustments for partial pressures and composition. The isentropic relations are emphasized as essential for accurate calculations, particularly for the temperature and pressure changes. Overall, understanding isentropic processes and applying the correct equations are crucial for solving the exam question effectively.
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Hello.
I have a thermodynamics exam tomorrow. This is a past exam question and I'm not doing very well with it. If anyone has any ideas please help!

A charge enters a spark ignition engine at 330K and 1 bar, and is isentropically compressed through a ratio of 7:1. Estimate the temp and pressure at the end of the compression, taking the charge to be:
a) pure air with constant specific heat.
b) a stoichiometric mixture of air and octane(C8H18) with variable specific heats (neglect residual gases). :eek:
 
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Well, I guess the test was yesterday. How'd you do?

Anyway:

1) First of all, you must understand the significance of isentropic.

Then the compression is 7:1 so the charge, air, is compressed to 7 bar.

Then solve the temperature using the appropriate equation.

2) similar to 1) but now a mixture of stoichiometric mixture of air and octane(C8H18) - so determine the partial pressures and composition, which influences specific heat. Same compression ratio.
 
Astronuc said:
Well, I guess the test was yesterday. How'd you do?

Anyway:

1) First of all, you must understand the significance of isentropic.

Then the compression is 7:1 so the charge, air, is compressed to 7 bar.

Then solve the temperature using the appropriate equation.

2) similar to 1) but now a mixture of stoichiometric mixture of air and octane(C8H18) - so determine the partial pressures and composition, which influences specific heat. Same compression ratio.

That's not true. You need to use the isentropic relations. Compression ratio is a ratio of volumes, not pressures. The three isentropic relations are:
(T2/T1) = (v1/v2)^(k-1)
(T2/T1) = (P2/P1)^(k-1)/k
(P2/P1) = (v1/v2)^k
These are estimations based on constant specific heats. To be more accurate and use variable specific heats, you will need to use vr and Pr, relative specific volume and relative pressure. However, since the question says estimate, using the isentropic relations should be good. So, if (v1/v2) = 7, then P2 = P1*7^1.4 (k = 1.4 for air). Likewise, T2 = T1*7^0.4

As said in the other thread, I'm not 100% sure how to do part b off the top of my head.
 
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