Thermodynamic heat power problem

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To determine the power required for a carpet steamer to convert 2 kg of snow or ice at -10°C to steam in 5 minutes, the relevant thermodynamic equations include Q=mCΔT, Q=mHv, and Q=mHf. The calculations involve accounting for the energy needed to raise the temperature of the ice, melt it, and then convert the resulting water to steam. An initial attempt at solving the problem involved incorrect division of the given values, leading to an inaccurate result. The correct power needed for the steamer is calculated to be 20156 W. Understanding the thermodynamic principles and correctly applying the equations is crucial for solving such problems.
pasiman94
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Homework Statement



Carpet steamer marketed for Greenland. Add up to 2 kg of snow or ice (no colder than -10°C) that will be converted to steam within 5 minutes. How powerful would the steamer need to be to make this claim? Know that 2108 J/kg K; Hf= 3.24*10^5 J/kg; Cwater= 4184 J/kg K; Hv = 2.26*10^6 J/kg.

Homework Equations



Q=mCΔT
Q=mHv
Q=mHf

The Attempt at a Solution


attempted to solve the equation by dividing all the givens by two and then adding them all up, however I know that it is not correct and the answer is P = 20156 W

Thanks
 
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pasiman94 said:

Homework Statement



Carpet steamer marketed for Greenland. Add up to 2 kg of snow or ice (no colder than -10°C) that will be converted to steam within 5 minutes. How powerful would the steamer need to be to make this claim? Know that 2108 J/kg K; Hf= 3.24*10^5 J/kg; Cwater= 4184 J/kg K; Hv = 2.26*10^6 J/kg.

Homework Equations



Q=mCΔT
Q=mHv
Q=mHf

The Attempt at a Solution


attempted to solve the equation by dividing all the givens by two and then adding them all up, however I know that it is not correct and the answer is P = 20156 W

Thanks

What was the logic behind your approach? Why do you think it failed?
 
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