Thermodynamic question involving work

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The discussion focuses on deriving the work done by a reversible function transitioning from P1V1 to P2V2, expressed as W = (P1V1 - P2V2)/(x - 1) using the relation PVx = C. Participants emphasize the need to compute the definite integral of PdV from V1 to V2, with pressure expressed in terms of volume through the equation PVx = constant. There is a suggestion to substitute the constants appropriately during integration to ensure accuracy. The conversation highlights the importance of understanding how pressure and volume change throughout the process, maintaining the relationship defined by the equation. Overall, the participants seek clarity on integrating the function and justifying the constants involved.
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Homework Statement


Show that the work done by a reversible function from P1V1 to P2V2 is

W = (P1V1 -P2V2)/ (x - 1)

using the relation PVx = C where X and C are constants


Homework Equations



dW = PdV

The Attempt at a Solution



I'm going to have to update this more when i get home because i forgot my textbook and notebook

Basically what I did was draw a graph from P1V1 to P2V2 and the whole point is to find the area underneath the curve


My problem is I'm not sure how to include the change in pressure and the change in volume in this integral.

I'm basically getting (x-y)/xy where x and y are different volumes

Like i said i will update my work when i get home, but any help for now will be appreciated
 
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dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)
 
pabloenigma said:
dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)

funny thing is that if you are right i did that, and i guess i must have messed up my algebra. Curse the few first days of school
 
pabloenigma said:
dw =PdV,there you are.
So to compute work,all you need to do is compute the definite integral of PdV from V1 to V2.
Express P in terms of V,by using the equation PVx=constant(say k),ie P=kV-x

Now Integrate KV-x from V1 toV2,and you are done,provided you put the limits nicely(substitute k=P1V1x in the 2nd term and k=P2V2x in the first term)

I did do that, but do you justify that k=P2V2x=P1V1x?
 
In your question, PVx=constant is the equation of the process,ie this equation characterizes and defines the process the system is made to go through.This defines the way P and V of the system changes. So, P and V of the system always saties this equation. If P1V1, P2V2,P3V3 , etc are pressure and volume of the system in different points of time, then for all thes states, PiVi=k is satisfied.

So from the initial and final states we get

P1V1= P2V[/SUB]2[/SUB]=k.
Got it?
 
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