Thermodynamics -- calculating fluid mass

AI Thread Summary
The discussion revolves around a thermodynamics problem involving fluid compression and expansion, where the user struggles to calculate the mass of the fluid. The specific volume was initially misreported as 0.05 m³/kg instead of the correct 0.5 m³/kg, which led to confusion in calculations. Participants emphasized using the specific volume to determine mass and suggested employing the relationship between pressure and volume during the processes. The user ultimately confirmed understanding of the p-v diagram and the calculations needed to arrive at the correct mass of 0.0753 kg. The conversation highlights the importance of accurate values and fundamental principles in thermodynamic calculations.
BurningUrge
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This is quite possibly very basic, but I have a horrible habit of forgetting basics as I move up the ladder in difficulty during the semester. This is a question regarding Thermodynamics, taken from Chapter 1; Introduction and the First Law of Thermodynamics of the book Applied Thermodynamics for Engineering Technologist (5th Edition).

I am including the whole question just to avoid any misunderstandings.

Homework Statement


A fluid at 0.7 bar occupying 0.09m3 is compressed reversibly to a pressure of 3.5 bar according to law pvn = constant. The fluid is then heated reversibly at constant volume until the pressure is 4 bar; the spesific volume is then 0.05m3 / kg. A reversible expansion according to a law pv2 = constant restores the fluid to its initial state. Sketch the cycle to a p-v diagram and calculate:

i) The mass of fluid present (THIS is the one I cannot seem to figure out.. basics be damned)
ii) the value of n in the first process.
iii) the net work of the cycle.

Homework Equations


It is a fluid, not explicitly stated to be gas or liquid, so the basic pv = nRT doesn't necessarily apply here.

The Attempt at a Solution


I'm stumped, really. I have the answer (0.0753 kg) but I cannot figure out how to get to it.
 
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BurningUrge said:
Sketch the cycle to a p-v diagram and calculate:
Did you do that?

To get the mass, you will need to use the specific volume given.
 
BurningUrge said:
I have the answer (0.0753 kg) but I cannot figure out how to get to it.
I just calculated it myself, and I'm off by a factor of 10. Could you please check all the numerical values you have given in the problem?
 
Okay, so I rechecked the values, and the Spesific volume is meant to be 0.5, NOT 0.05. One slight tap too much on the 0 there.

Also, I did sketch the p-v diagram, yes. I'm pretty sure I got the understanding of how the process looks.

And when you say that I need to use Spesific volume, it strikes me how stupid I have actually been trying to figure this out. With that in mind, which formula would you suggest looking into for calculating the mass when I don't actually have the current volume? It's a pvn = constant, so I can't figure it out with the p1V1 = p2V2
 
BurningUrge said:
Okay, so I rechecked the values, and the Spesific volume is meant to be 0.5, NOT 0.05. One slight tap too much on the 0 there.
Good, then I get the correct result.

BurningUrge said:
Also, I did sketch the p-v diagram, yes. I'm pretty sure I got the understanding of how the process looks.
Then you should see that there are two processes that link the initial state to the unknown volume.
 
DrClaude said:
Then you should see that there are two processes that link the initial state to the unknown volume.

Yes there is. The 1 -> 2 and 3 ->4 both link the process from the initial volume to the unknown. Does it have anything to do with the pv2 = constant that is the exponent for the revesible process happening in 3 -> 4?

Or put in this way, I can figure out the volume using p1V12 = p3V32, where V3 = V2
 
BurningUrge said:
Or put in this way, I can figure out the volume using p1V12 = p3V32
Correct.
 
Then I have my answer and I am greatly appreciative of your help. Thank you very much!
 
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