Thermodynamics: Carnot efficiency

AI Thread Summary
The discussion focuses on calculating the power consumption of a heat pump operating at 25% of Carnot efficiency for heating and cooling in varying seasonal temperatures. In winter, the efficiency is calculated as 0.25, while in summer, it drops to approximately 0.1429 due to the temperature difference. The key equation used is n = Q_hot/W_cycle, where Q_hot represents the heat transfer rate. The user initially struggled with determining Q for each case but ultimately resolved the issue. The conversation highlights the importance of understanding thermodynamic efficiency in practical applications like heat pumps.
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Homework Statement



In one location, the average daily temperature varies sinusoidally between 35C in summer and 0C in winter. The ground temperature below 2 m underground is the annual average temperature. A heat pump / air conditioner unit must deliver air to a house at 30C in winter and 15 C in summer. If the unit operates at 25% of Carnot efficiency, how much power is consumed per each kW of heating or cooling provided if the unit operates air source and ground source in winter and summer?

Homework Equations



How do i get Q for each case?

The Attempt at a Solution



Winter: efficiency n = 0.25(1 - 0/30) = 0.25
Summer: n = 0.25(1 - 15/35) = 0.1429

n = Q_hot/W_cycle, so we need Q_hot, where both W and Q are rates of work and heat transfer
 
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nevermind i figured it out
 
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