Thermodynamics- Charging an air tank

AI Thread Summary
The discussion revolves around calculating the final temperature and mass of air in a scuba diver's tank after it is filled from a compressed air line. The initial conditions of the tank are 20 psia and 70°F, while the filling conditions are 120 psia and 100°F. The participant expresses uncertainty about how to approach the problem, considering mass and energy balances but unsure about their legality. A suggestion is made to use the ideal gas law to find the final temperature in terms of the mass of air injected, allowing for a solution with one unknown. The conversation emphasizes the importance of using property tables for specific volume as an alternative to the ideal gas law due to the high pressure involved.
MacLaddy
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Homework Statement



A scuba diver's 2ft3 air tank is to be filled with air from a compressed air line at 120 psia and 100F. Initially, the air in this tank is at 20 psia and 70F. Presuming that the tank is well insulated, determine the temperature and mass in the tank when it is filled to 120 psia.


Homework Equations



m_ih_i = m_2u_2 - m_1u_1

From my property tables booklet.

h_1 = 133.86 Btu/lbm
u_1 = 90.33 Btu/lbm


The Attempt at a Solution



Not entirely sure where to take this. If I do just a mass balance I'll get m_i = m_2-m_1, but I'm not sure how this will help me.

If I could do an energy balance like this h_i=u_2-u_1, then it would be fairly simple to solve for the internal energy at the second state, and find the temperature. However, I don't think that's a legal move.

I've played with specific volumes, tried to find flow rates, and played with the Ideal Gas Law.

Any help is appreciated,

Thanks,
Mac
 
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Thank you Mod's for moving this to the appropriate forum. I wasn't sure exactly what category Thermodynamics fell into.
 
MacLaddy said:

Homework Statement



A scuba diver's 2ft3 air tank is to be filled with air from a compressed air line at 120 psia and 100F. Initially, the air in this tank is at 20 psia and 70F. Presuming that the tank is well insulated, determine the temperature and mass in the tank when it is filled to 120 psia.


Homework Equations



m_ih_i = m_2u_2 - m_1u_1

From my property tables booklet.

h_1 = 133.86 Btu/lbm
u_1 = 90.33 Btu/lbm


The Attempt at a Solution



Not entirely sure where to take this. If I do just a mass balance I'll get m_i = m_2-m_1, but I'm not sure how this will help me.

If I could do an energy balance like this h_i=u_2-u_1, then it would be fairly simple to solve for the internal energy at the second state, and find the temperature. However, I don't think that's a legal move.

I've played with specific volumes, tried to find flow rates, and played with the Ideal Gas Law.

Any help is appreciated,

Thanks,
Mac
How much mass m1 is in the tank to start with? Let mi represent the mass of air injected into the tank. How many moles are in the tank at the beginning and, in terms of mi, how many moles are in the tank at the end? Call T the final temperature. Use the ideal gas law to calculate the value of T in terms of mi. Now you only have 1 unknown. u2 is a function of T, which in turn is a function of mi. So use your equation m_ih_i = m_2u_2 - m_1u_1 and your table to solve for mi.

Incidentally, considering the magnitude of the pressure, maybe you're not comfortable using the ideal gas law. If your table has specific volume as a function of temperature and pressure, you can use that instead.

Chet
 
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