Thermodynamics/Entropy Question

[turgrid]

Homework Statement

An 82-kg parachutist descends through a vertical height of 350 m with constant speed. Find the increase in entropy produced by the parachutist, assuming air temperature of 21 degrees C.

2. Relevant Equation
S = Q/T

The Attempt at a Solution

I believe I can find work via W = mgh or (82)(9.81)(350) = 281,547 J. What can I do from there.

Thanks in advance.

 

[turgrid]

Can I assume the body temperature is 37 degrees C? Do I need to? I cannot figure out how to find hot temperature and heat transfered. Are there any ideas on how I can convert W in this situation into something useful to further the problem? Any hints towards the right direction would be appreciated.

 

[ogb p]

The increase in entropy produced by the parachutist can be calculated using the equation S = Q/T, where S is the change in entropy, Q is the heat absorbed by the system (the parachutist), and T is the temperature at which the heat is absorbed.

In this case, the heat absorbed by the parachutist is equal to the work done on the system (W = mgh) which is 281,547 J. The temperature at which this heat is absorbed is given as 21 degrees C, which is equivalent to 294.15 K.

Therefore, the increase in entropy can be calculated as S = (281,547 J) / (294.15 K) = 957 J/K. This means that the entropy of the system (the parachutist) has increased by 957 J/K during the descent.

It is important to note that this is not the total change in entropy, as there may be other factors (such as air resistance) that also contribute to the overall increase in entropy. However, this calculation provides an estimate of the increase in entropy caused by the parachutist's descent.