Thermodynamics Homework: Solving the Mystery of Internal Energy Change

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SUMMARY

The discussion centers on the internal energy change in an adiabatic process, specifically addressing the first law of thermodynamics. It is established that for an adiabatic process, the change in internal energy (ΔU) is equal to the negative of the work done (W) by the gas on its surroundings, expressed as ΔU = -W. In scenarios where the surroundings perform work on the gas, W is negative, resulting in a positive ΔU, which leads to an increase in the gas temperature despite no heat transfer occurring. This phenomenon is exemplified by the compression of air in a bicycle pump.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Knowledge of adiabatic processes
  • Familiarity with the concept of work in thermodynamics
  • Basic principles of gas behavior under compression
NEXT STEPS
  • Study the implications of the first law of thermodynamics in various processes
  • Explore detailed examples of adiabatic processes in real-world applications
  • Learn about the mathematical derivation of work done in thermodynamic systems
  • Investigate the relationship between temperature changes and work in gases
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Students studying thermodynamics, educators teaching physics concepts, and anyone interested in understanding the principles of energy changes in gases during adiabatic processes.

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Homework Statement


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Homework Equations


Conceptual qn

The Attempt at a Solution



work is done in gas but how can internal energy change?
there is no heat flow since it is an adiabatic process[/B]
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
From the first law, for an adiabatic process, ##\Delta U=-W##, where W is the work done by the gas on the surroundings. In this situation, W is negative (the surroundings do work on the gas), so that ##\Delta U## is positive. The temperature of the gas actually rises, even though no heat was transferred to the gas. This is the same thing that happens when you compress air with a bicycle pump.

Chet
 

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