How Is Actual Power Calculated in a Turbine with Given Isentropic Efficiency?

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SUMMARY

The actual power produced by a turbine with an isentropic efficiency of 0.85, expanding steam from 4 MPa and 400°C to 10 kPa, is calculated using the equation ηt = (m(h1-h2))/(m(h1-h2s)) = (W act) / (W max). The user initially miscalculated h2 by not applying the correct formula, h2 = h1 - ηt(h1 - h2s). After correcting this, the user confirmed the accuracy of their results. The flow rate of steam is 10 kg/s, which is crucial for determining the actual power output.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically isentropic processes.
  • Familiarity with steam tables for enthalpy and entropy values.
  • Knowledge of turbine efficiency calculations.
  • Ability to perform calculations involving flow rates and energy equations.
NEXT STEPS
  • Study the application of steam tables for various pressures and temperatures.
  • Learn about the derivation and application of the isentropic efficiency equation in turbine analysis.
  • Explore advanced turbine performance metrics and their implications on power output.
  • Investigate the impact of varying flow rates on turbine efficiency and power generation.
USEFUL FOR

Mechanical engineers, thermodynamics students, and professionals involved in turbine design and performance analysis will benefit from this discussion.

dzj633

Homework Statement


Steam at a pressure of 4 MPa and 400 C and flow rate of 10 kg/s is expanded in a turbine to a pressure of 10 kPa. If the isentropic efficiency of the turbine is 0.85 then the actual power produced by the turbine is?

Homework Equations

:[/B]
ηt= (m(h1-h2))/(m(h1-h2s)) = (W act) / (W max)
s2s=s1
s2s=sf +x(sfg) <~~ To get quality
h2=hf +x(hfg)

The Attempt at a Solution


I started by looking up enthalpies and entropies at state one and two. Since s2s = s1, i used sf and sfg of P2 to find the quality and used that quality to find h2. I substituted all known values into the isentropic efficiency equation and i found h2s. After that, i plugged in all known values back into the Isentropic Eff eqn to solve for Wact and its incorrect. Did i miss a step or did them incorrectly?
 
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dzj633 said:

Homework Statement


Steam at a pressure of 4 MPa and 400 C and flow rate of 10 kg/s is expanded in a turbine to a pressure of 10 kPa. If the isentropic efficiency of the turbine is 0.85 then the actual power produced by the turbine is?

Homework Equations

:[/B]
ηt= (m(h1-h2))/(m(h1-h2s)) = (W act) / (W max)
s2s=s1
s2s=sf +x(sfg) <~~ To get quality
h2=hf +x(hfg)

The Attempt at a Solution


I started by looking up enthalpies and entropies at state one and two. Since s2s = s1, i used sf and sfg of P2 to find the quality and used that quality to find h2. I substituted all known values into the isentropic efficiency equation and i found h2s. After that, i plugged in all known values back into the Isentropic Eff eqn to solve for Wact and its incorrect. Did i miss a step or did them incorrectly?
Please show the details of your calculations so I can check your numbers.
 
Chestermiller said:
Please show the details of your calculations so I can check your numbers.

I figured out what I did wrong, I used: h2=h1-nt(h1-h2s) to solve for h2 and my number was correct.
 

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