Thermodynamics- total kinetic energy and rms velocity

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Discussion Overview

The discussion revolves around calculating the total kinetic energy and root mean square (rms) velocity of helium gas under specific conditions, including its volume, pressure, and density. Participants explore the relationships between these quantities using thermodynamic equations, with a focus on ideal gas behavior.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses confusion about applying the equations for kinetic energy and pressure-volume relationships in the context of helium gas.
  • Another participant asks about the temperature of the gas and its relationship to kinetic energy, suggesting that temperature can be derived assuming ideal gas behavior.
  • A participant shares partial solutions and attempts to clarify the derivation of kinetic energy equations, but expresses uncertainty about specific rearrangements needed to find rms velocity.
  • Some participants note that as temperature increases, kinetic energy also increases, referencing the equation relating kinetic energy to temperature.
  • One participant offers a method to calculate rms velocity and total kinetic energy, demonstrating the use of given values and rearranging equations, while acknowledging multiple approaches to the problem.

Areas of Agreement / Disagreement

Participants generally agree on the relationships between temperature, kinetic energy, and rms velocity, but there is no consensus on the specific calculations or methods to arrive at the final answers. Some participants express confusion and seek clarification on certain steps.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about ideal gas behavior, the dependence on accurate unit conversions, and the clarity of mathematical steps involved in the derivations.

Who May Find This Useful

This discussion may be useful for students or individuals studying thermodynamics, particularly those interested in the kinetic theory of gases and the application of mathematical relationships in physical chemistry.

xxx23
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Find total kinetic energy and root mean square velocity of the molecules of 10 liters of helium gas at an equilibrium pressure of 105 N m−2. Density of helium is 0.1786 gram/liter.


I am having trouble with the question, I know:

K=(Nm<v^2>)/2

PV=(Nm <v^2>)/3

but I am not sure how to apply this.

Any help would be appreciated.
 
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xxx23 said:
Find total kinetic energy and root mean square velocity of the molecules of 10 liters of helium gas at an equilibrium pressure of 105 N m−2. Density of helium is 0.1786 gram/liter.
Can you find the temperature? What is the relationship between temperature and kinetic energy?

AM
 
I have partial solutions from my tutorial but they are not making too much sense...

From the above equations, it goes:

K= 1/2 Nm <v>^2 so if divide each side by V
K= 1/2 ρ V <v>^2

from here the solution goes:

PV=1/3 Nm <v>^2

K=3/2 PV I can see that 2K=3PV

but i do not understand where the following equations come from:


K=1/3 ρ V <v>^2 because this is what i need to rearrange to find Vrms.
 
You did not answer my questions.

AM
 
I know that as the temp increases so does the kinetic energy.

1/2 m <v>^2 = 3/2 KT
 
xxx23 said:
I know that as the temp increases so does the kinetic energy.

1/2 m <v>^2 = 3/2 KT
You haven't answered my first question: what is the temperature of the Helium? (hint: assume it is an ideal gas).

AM
 
I'm not sure if you still need help with this question, but I'll show how I'd work it out:

Firstly, to find the RMS (root mean squared) velocity of the molecules, we'll start with your equation,

PV=(Nm <v^2>)/3 Now we don't know N, and while we could calculate it, its easier to rearrange this equation to form,
P = (Nm<v^2>)/3V (multiplying both sides by V)
P = (1/3)p<v^2> (using Nm/V = p (density) )

Now we know p the density, and P the pressure so rearrange
<v^2> = 3P/p
<v^2> = 3 x 105 / (0.1786 x 10^-3 / 10^-3 ) [ensuring p is in kg/m^3]
<v^2> = 1763.7178...
RMS = 42.0 ms^-1 (3sf) [square root the <v^2>]

Secondly to find the total Kinetic energy

Start with what we have, so P = Nm<v^2> / 3V
and K= 1/2 Nm <v^2>

So 3PV = Nm<v^2>
3PV/2 = 1/2 Nm<v^2>
and since K = 1/2 Nm<v^2>
We can state that K = 3/2 PV and can now substitute your values into find the answer.

There are many ways of solving these as they are all rearrangements of the same equation.
 

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