Just before reading, i am posting this as this question seemed way to easy to solve in my assignment, problems aren't usually this easy ! haha.
I need to find V0, i originally just found the voltage at that node using KCL which was straight forward, but in my lecture notes the lecturer added a voltage source inbetween the two terminal, but he was trying to find thevenins equiv voltage, my question is, should i be adding the vth (or vo whatever you want to call it) voltage source between the terminals where v0 is and have a current going upwards (ith) in this case and solve for vth or vo? or can i just find the voltage at that node
The Attempt at a Solution
I just took kcl at the vo node and got this:
V/(j754) + 2(ix) + (V-(16∠45°))/(-j53.05)) = 0?
If i was to add the voltage source between the terminals, my KCL equation would be the same except instead of it equalling 0 it would equal Ith
V/(j754) + 2(ix) + (V-(16∠45°))/(-j53.05)) = Ith
i just need clarification which method is correct, thankyou!