(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate the electric field at a point midway between the two charges on the x-axis.

Magnitude:

Direction below the x axis in degrees.

2. Relevant equations

F=Ke*q/(h)^2

3. The attempt at a solution

What I did 1st is since the charge 3.00 is in the midpoint..calculated .500sin60 to get .434

..then I just plugged it in the formula 8.99*10^9 * 3.00*10-6/(.434)^2 to get 144 N

for the two charges on the x axis..

I just divided the distance .500 by 2 to get .250 m and plugged in each charge seperately. I got 1.15*10^3 N and 719 N. Would you have to add them all up to get the total magnitude..and for the direction, I think you need to divide the two charges on the x axis and take arc tan right? I'm not too sure, but I keep getting this wrong..someone plz help.

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# Homework Help: Three charges and midpoint

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