1. The problem statement, all variables and given/known data Three charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate the electric field at a point midway between the two charges on the x-axis. Magnitude: Direction below the x axis in degrees. 2. Relevant equations F=Ke*q/(h)^2 3. The attempt at a solution What I did 1st is since the charge 3.00 is in the midpoint..calculated .500sin60 to get .434 ..then I just plugged it in the formula 8.99*10^9 * 3.00*10-6/(.434)^2 to get 144 N for the two charges on the x axis.. I just divided the distance .500 by 2 to get .250 m and plugged in each charge seperately. I got 1.15*10^3 N and 719 N. Would you have to add them all up to get the total magnitude..and for the direction, I think you need to divide the two charges on the x axis and take arc tan right? I'm not too sure, but I keep getting this wrong..someone plz help.