Three part weightlifter question

  • Thread starter Thread starter physicsgurl12
  • Start date Start date
AI Thread Summary
To calculate the work done by the weightlifter lifting a 40kg barbell 0.50m, the formula w=fd is applied, where the force is determined using f=ma with gravity's acceleration at 9.8 m/s². The total work for one lift is calculated, and for 20 repetitions, the total energy expended is found, factoring in a 25% efficiency rate. This energy expenditure can then be converted into the equivalent number of 400-calorie donuts she can consume daily to replenish that energy. The discussion emphasizes the application of physics equations to solve real-world fitness scenarios. Understanding these calculations aids in optimizing workout routines and dietary needs.
physicsgurl12
Messages
184
Reaction score
0

Homework Statement



A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 40kg barbell straight up at a distance of .50m.
a. how much work does the weightlifter do to lift the barbell one time?
b. if the weightlifter does 20 reps a day what total energy does she expend on lifting? assume 25% efficency.
c. How many 400 calorie donuts can she eat a day to supply that energy.

Homework Equations



w=fd f=ma


The Attempt at a Solution


w=fd w=f*.50m
f=40kg*a ?/
 
Physics news on Phys.org
Use the work energy theorem, the barbell has zero velocity at both the top and bottom of the rep.
 
Your acceleration "a" is the acceleration of gravity: g=9.8 m/s2.
With what you already have you should be able to find the work w...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top