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can anyone explain me how to beggin because i am confused.. i will use E(X+Y+Z/X)=E(X/X)+E(Y/X)+E(Z/X)=? for the first one?

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- Thread starter ParisSpart
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- #1

- 129

- 0

can anyone explain me how to beggin because i am confused.. i will use E(X+Y+Z/X)=E(X/X)+E(Y/X)+E(Z/X)=? for the first one?

- #2

HallsofIvy

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can anyone explain me how to beggin because i am confused.. i will use E(X+Y+Z/X)=E(X/X)+E(Y/X)+E(Z/X)=? for the first one?

I think you need to go back and look at the problem again. I don't know what you mean by "how many differents values have the random values E(W/X) and E(W/X+Y)?"

How many different values" of

It's not all that difficult to determine the [itex]6^3= 216[/itex] combinations of three dice. W ranges in value from 3 to 18.

- #3

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Assuming you mean E((X+Y+Z)/X), that's a good start. E(X/X) is obvious. Since X and Y are independent, can you expand E(Y/X) into separate functions of X and Y?E(X+Y+Z/X)=E(X/X)+E(Y/X)+E(Z/X)=?

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