Throw Up Problem without given velocity or time

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The discussion revolves around solving a physics problem involving a stone thrown upward from a bridge, which falls into a river 63.3 meters below after 2.20 seconds. The key tasks are to determine the stone's speed as it passes the bridge and the maximum height it reaches above the bridge. The correct approach involves using kinematic equations, particularly focusing on the initial velocity and the effects of gravity. The initial velocity can be derived from the known distance and time, while the maximum height can be calculated using the conservation of energy principle. The answers provided are 17.99 m/s for the speed and 16.5 m for the maximum height.
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"Throw Up" Problem without given velocity or time

Homework Statement


A stone is thrown straight upward from the edge of a bridge so it passes the bridge on the way down and falls in the river 63.3m below. The stone strikes the water 2.20s after it passes the bridge. Calculate
a) the speed of the stone as it passes the bridge
b)the maximum height above the bridge which the stone attained
(assume there is no air resistance)

Homework Equations


There was none given, so I am assuming that its the normal kinematic equations to solve for them such as V=Vo+A*t

The Attempt at a Solution


I literally spent four hours tryinng to solve this problem. I tried manipulating my coordinate system, but nothing seemed to work. However, I do know that the answer for A is 17.99m/s and B is 16.5m
 
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I know those are the answers because my teacher gave us the answers prior to the assignment, just so it might guide us to figure out how to actually solve this impossible problem.
 


There are 2 others SUVAT equations and find the one that suit with given data.
 


Treat it as 2 separate problems.

First you need to find the initial velocity of a fall under gravity. You know the distance and time. Should be easy.

Once you have found that, you can use the initial velocity to find the max height. (hint an object returns to the starting point with the same speed it was thrown up with.)
 


But it was thrown off of a bridge into the water so the starting and ending points are at different levels. Also i wasnt given an initial velocity.
 


By conservation of energy, the speed it was thrown up from the bridge, is equal to the speed when it passes down the same level as it plunges down into the water below.
 


Thanks you guys, got it (:
 
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