1. The problem statement, all variables and given/known data Ball A is thrown vertically by speed 40 m/s. After 1 second, Ball B is thrown vertically also by speed 47.5 m/s. What height from ground will they pass each other? ( g = 10m/s2 ) 2. Relevant equations s = vt + ½at2 t = v/g v2 = v02 + 2as 3. The attempt at a solution Time A to reach the max height is t = v/g = 40/10 = 4 s I don't understand. Because there is plus of 1 sec for ball B.