- #1

Said Ahmad

- 8

- 1

## Homework Statement

Ball A is thrown vertically by speed 40 m/s. After 1 second, Ball B is thrown vertically also by speed 47.5 m/s.

What height from ground will they pass each other? ( g = 10m/s

^{2})

## Homework Equations

s = vt + ½at

^{2}

t = v/g

v

^{2}= v

_{0}

^{2}+ 2as

## The Attempt at a Solution

Time A to reach the max height is t = v/g = 40/10 = 4 s

I don't understand. Because there is plus of 1 sec for ball B.