Raresss
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How can I calculate the thrust of an underpressure tank of air when the valve is released? If you can, please, explain in detail. Thank you!
The thrust produced by an underpressure tank of air when the valve is released can be calculated using the pressure in the tank and the area of the orifice. For example, if the pressure is 1 MPa above ambient and the orifice diameter is 12 mm, the thrust would be approximately 1 Newton. Key concepts include mass flow rate, velocity of the escaping gas, and Bernoulli's principle as an approximation for calculations. Understanding the distinction between "underpressure" and "under pressure" is crucial for accurate communication in this context.
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More than the ambient pressureBystander said:"Underpressure?" Less than ambient?
Pressure "under" what? Do you mean when it's running out?Raresss said:More than the ambient pressure
I can see that now. In English, underpressure and "underweight" (compound words) have different meanings from when the two words are separated by a space; hence my confusion. If this were a German forum, things might be different. . .CWatters said:The OP just means the thrust produced by air escaping from a cylinder of compressed air.
Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
Raresss said:Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?
sophiecentaur said:If this were a German forum, things might be different. . .![]()
Your force is the normal force, and your pressure is the surface pressure. We can't use those in my problem. The thrust is based on other variables . Check out this link to find out more : https://en.wikipedia.org/wiki/Thrustmrspeedybob said:Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?