Thrust of an underpressure tank of air

  • #1
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How can I calculate the thrust of an underpressure tank of air when the valve is released? If you can, please, explain in detail. Thank you!
 

Answers and Replies

  • #2
"Underpressure?" Less than ambient?
 
  • #3
"Underpressure?" Less than ambient?
More than the ambient pressure
 
  • #4
More than the ambient pressure
Pressure "under" what? Do you mean when it's running out?
 
  • #5
The OP just means the thrust produced by air escaping from a cylinder of compressed air.

Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
 
  • #7
The OP just means the thrust produced by air escaping from a cylinder of compressed air.

Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
I can see that now. In English, underpressure and "underweight" (compound words) have different meanings from when the two words are separated by a space; hence my confusion. If this were a German forum, things might be different. . . :smile:
 
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  • #8
Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?
 
  • #9
Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?

Bernoulli should be a good approximation.

If this were a German forum, things might be different. . . :smile:

Not really. "Unterdruck" instead of "unter Druck" would result in the same confusion.
 
  • #10
Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?
 
  • #11
Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?
Your force is the normal force, and your pressure is the surface pressure. We can't use those in my problem. The thrust is based on other variables . Check out this link to find out more : https://en.wikipedia.org/wiki/Thrust
 

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