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How can I calculate the thrust of an underpressure tank of air when the valve is released? If you can, please, explain in detail. Thank you!
More than the ambient pressure"Underpressure?" Less than ambient?
Pressure "under" what? Do you mean when it's running out?More than the ambient pressure
I can see that now. In English, underpressure and "underweight" (compound words) have different meanings from when the two words are separated by a space; hence my confusion. If this were a German forum, things might be different. . .The OP just means the thrust produced by air escaping from a cylinder of compressed air.
Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?
If this were a German forum, things might be different. . .![]()
Your force is the normal force, and your pressure is the surface pressure. We can't use those in my problem. The thrust is based on other variables . Check out this link to find out more : https://en.wikipedia.org/wiki/ThrustWould it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?