Time dependent dispersion (Quantum Mechanics)

emol1414
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Homework Statement


The initial wave function \Psi (x,0) of a free particle is a normalized gaussian with unitary probability. Let \sigma = \Delta x be the initial variance (average of the square deviations) with respect to the position; determine the variance \sigma (t) in a moment later.

Homework Equations


I'm not sure which equations should I start from... but, as for a gaussian distribution, I'm thinking of
\Psi (x,t) = \int^{\infty}_{-\infty} a(k) e^{i(kx - \omega t)} dk,
being

a(k) = \frac{A \sigma}{\sqrt{2\pi}} \exp{\left[-\frac{(k - k_0)^2 {\sigma}^2}{2}\right]}


The Attempt at a Solution


I don't know how to start it... once I describe the wave function, find A, I don't know how to construct this time dependent dispersion. I know the packet will 'spread', and its width will increase, but no ideas on how to describe this in terms of the dispersion... I know the result is \sigma (t) = \sqrt{\sigma^2(0) + (\frac{\hbar t}{2m \sigma(0)})^2}
 
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Sorry you haven't gotten an answer on this yet, but if it's still relevant: I'd start by determining the dispersion relation \omega(k) for the particle and plugging that in. The eventual goal is to take the explicitly time-dependent expression you have,
\Psi (x,t) = \int^{\infty}_{-\infty} a(k,\sigma) e^{i(kx - \omega t)} dk
and rewrite it as an implicitly time-dependent expression
\Psi (x,t) = \int^{\infty}_{-\infty} a(k,\sigma(t)) e^{ikx} dk
which should give you the expression you need.
 
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