matheinste said:
It can be semantically confusing and so we need some agreed definitions for our purposes. Let us define the length of time passed as a number of seconds. Let us define the basic period of time as one second, that is, the duration of time between two ticks of a clock. Let us also allow ourselves access to a master clock which ticks along unchagingly for all observers. This means it has a constant basic period for all observers. Of course such a clock does not exist in nature.
Shouldn't be a problem. For our purposes, we can arbitrarily define some clock as our master clock. It may not be visible to all observers on all occasions, but if they can't see it, they can calculate what it would say, so we can call it a master clock for the sake of definitions.
matheinste said:
Now for any clock the length of time passed and the basic period for the same amount of time on the master clock are reciprocal, if one increases the other decreases.
Right, so if there are two interpretations of what dilation refers to--(1) the total number of units, (2) the size of each unit--the difference between them is a matter of reciprocity, and the dilation factors in the equations expressing each definition should be reciprocal.
(1) \; \Delta t'_{1} = \gamma \Delta t_{1}
(2) \; \Delta t'_{2} = \gamma^{-1} \Delta t_{2}
Here I use prime symbols simply to indicate output, what we might call the result of time dilation, "dilated time", depending on how we understand the word. In each case, we select some clock as our arbitrary standard, "master clock" if you like. And this is indeed what we find, with most authors calling (1) time dilation (and its output "dilated time"), but with a few authors, Lawden and Anthony, thinking of (2) as time dilation (and its output "dilated time"). A significant difference in terminology!
In
(1), the formula converts a given time interval recorded by our arbitrarily selected "master clock" (the invariant interval between two events on our master clock's worldline) into the corresponding coordinate time in some frame where the master clock is moving. That's to say: the result is the invariant proper time interval between another pair of events, E_1 and E_2, the first of which is simultaneous in the frame where our master clock is moving with the beginning of our input interval, while E_2 is simultaneous in that same frame with the end of our input interval.
We dilate the total number of seconds (and contract the size of our seconds) relative to our arbitrarily chosen standard.
Equation
(2) converts the proper time between one pair of events on our master clock's worldline into the proper time between another pair of events, E_1 and E_2, on the worldline of a clock at rest in a frame where our master clock is moving, E_1 being simultaneous in the master clock's rest frame with the beginning of our input interval, and E_2 being simultaneous in the master clock's rest frame with the end of our input interval. Equivalently, it converts a coordinate time between E_1 and E_2 into the invariant proper time interval between them.
We dilate the size of our seconds (and contract the total number of them) relative to our arbitrarily chosen standard.
matheinste said:
However, and this is a possible area of confusion, there is a case where they can have the same value of 1. If we have a length of time passed of one second it is equal to the basic period of one second. So for a value of one second we have length of time passed equals one basic period of time. But if you dilate the basic period of time (relative to the master clock) to more than one second in length, you decrease the number of ticks, length of time passed, number of seconds, (relative to the master clock), to less than one.
But if you think of dilation as referring to the total number of seconds and dilate one second, the result is \gamma seconds. If you think of dilation as referring to unit size and dilate that, thus reducing the total, the result is \gamma^{-1} seconds. Not the same thing at all. This applies no matter whether the length of time of the input is one unit or any multiple of one unit. Nor does the effect depend on what units we use. Only when our input is zero does the effect vanish (unless there's some spatial component too, in which case we need the full Lorentz transformation).
matheinste said:
Also bear in mind that a moving (in fact any) clock records its own proper time, number of ticks, and this is always less than the number of ticks recording the difference between the necesary two staionary clock readings, coordinate time, which are required to record the time in the stationary frame whcih it is moving relative to. And what do less ticks for the same time imply? A longer (dilated) basic period.
Since there is no absolute master clock in nature, we have to specify what arbitrary standard we're using to define "less than" or "more than". See above. If we've converted a smaller total of ticks into a larger total of ticks, we've dilated our number of ticks (and contracted the size of our seconds). If we've converted a larger number of ticks into a smaller number of ticks, we've dilated the size of our seconds (and contracted the total of them).
matheinste said:
So dilation refers to the basic period being lenghened, made large, dilated, relative to another clock, and the length of time passed made a smaller number of the baisc periods, seconds, relative to the same other clock.
Not if, like Adams, Freund, Lerner, Petkov, Schröder and Taylor & Wheeler, we call the following operation time dilation and refer to \Delta t'_{1} as "dilated time":
(1) \; \Delta t'_{1} = \gamma \Delta t_{1}
But yes if, like Anthony and Lawden, we call the following operation time dilation and refer to \Delta t'_{2} as "dilated time":
(2) \; \Delta t'_{2} = \gamma^{-1} \Delta t_{2}