Time = distance/speed conversion problem

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The problem involves calculating the time it takes for light from the Sun to reach Mercury, given the speed of light and the distance to Mercury. The initial calculations incorrectly used miles per hour instead of miles per second for the speed of light, leading to an erroneous time conversion. The correct speed of light is approximately 186,000 miles per second, not 1.86 x 10^8 miles per hour. Additionally, the conversion from hours to minutes was misapplied; it should involve dividing by 60 instead of multiplying. With these corrections, the accurate time can be determined.
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Homework Statement


The velocity of light is 1.86 x 108 mi/hr. The distance of Mercury from the Sun is approximately 5.78 x 107 km. How many minutes will it take for light from the Sun to travel to Mercury?



Homework Equations


1 mi = 1.609 km
time = distance/speed
60 min/1 hr



The Attempt at a Solution


1.609 km/1 mi * 1.86 x 108 mi/hr = 2.99 x 108 km/hr

time = 5.78 x 107 km / 2.99 x 108 km/hr = 1.933 x 10-1 hr

60 min/1 hr * 1.933 x 10-1 hr = 115.98 x 10-1 min

Answer: 11.598 minutes.

That answer does not make sense to me. What did I do wrong here?
 
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I think you converted km to mi incorrectly.

1 kilometer = 0.621371192 miles
 
rock.freak667 said:
I think you converted km to mi incorrectly.

1 kilometer = 0.621371192 miles
Yes, so one mile is 1/.621371192 km= 1.60934400 miles which is what he used. And he was converting from miles to kilometers.

However, Mathnomolous, the speed of light is 1.86 x 108 miles per second, not miles per hour!

You should have divided by 60 to convert second to minutes, not multiplied to convert hours to minutes.
 
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Your speed of light is incorrect. It's not 2.99 x 108 km/hr, it's 2.99 x 108 m/s, which is something like 6.71 x 108 mi/hr or 186,000 miles per second.
 
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I typed the problem as it appears on my chemistry textbook. I also asked the professor to do the problem in class, with the same result. I never imagined the textbook had that kind of error. Thanks for the correction. I should be able to obtain the right answer now.
 
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