Time Interval between Rocket Explosions for Spaceship Tripulant

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SUMMARY

The discussion centers on calculating the time interval between two rocket explosions as perceived by a tripulant aboard a spaceship traveling at 0.7c. The actual distance between two students launching rockets is determined to be 71.4m, while the proper length of the spaceship is 21m. The time taken for the spaceship to cover the distance between the two students is calculated using the formula t = d/v, resulting in a time of 3.4 x 10^-7 seconds. The tripulant observes that the explosions are not simultaneous, prompting a request for further assistance in determining the time interval between the explosions.

PREREQUISITES
  • Understanding of special relativity concepts, including simultaneity and length contraction
  • Familiarity with the equation t = d/v for calculating time intervals
  • Knowledge of proper length versus observed length in relativistic contexts
  • Basic understanding of the speed of light (c) and its implications in physics
NEXT STEPS
  • Research the concept of simultaneity in special relativity and its implications for observers in different frames of reference
  • Study the effects of length contraction on moving objects, particularly in high-speed scenarios
  • Explore the Lorentz transformation equations to understand time dilation and spatial relationships in relativity
  • Investigate practical applications of relativistic physics in modern technology, such as GPS systems
USEFUL FOR

Students of physics, particularly those studying special relativity, educators teaching advanced physics concepts, and anyone interested in the implications of relativistic effects on time and space.

Jalo
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Homework Statement



Two students on the ground, separated 100m from each other, launch one rocket each vertically. The rocket explode at the same time for an observer, on the ground, that's midway between the rocket explosion. At the exact time the observer sees the rockets exploding a spaceship flies over his head, horizontally, at a speed of 0.7c. The ship length as seen by the observer is 15m.

(c)How much time goes by, to a tripulant of the spaceship, for the ship to complete the 100m between the two students?
(d)For a tripulant of the spaceship is the explosion of the rockets simultaneous? What's the time interval? (time between the first rocket explosion and the second, as seen by the tripulant)


Homework Equations



After solving the first two questions I've reached this data:
Actual distance between the two students = 71.4m
Spaceship length as measured by the tripulant = 21m

As to question (c) I used the equation t=d/v to solve it.

The Attempt at a Solution



(c) I think I've done her correctly. I've simply divided the length between the two students as seen by a tripulant in a ship by her speed:
t=71.4/0.7c=3.4*10^-7

(d) I know the explosions are not simultaneous, however I have no idea how I'm supposed to measure the time interval between the two explosions... If anyone could give me some hint, or some equation that could help me i'd be grateful. I've readen the whole relativity chapter of Serway's Physics for Scientists looking for something to help me without any luck.

Thanks, and a happy new year to everyone.
 
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Jalo said:

Homework Statement



Two students on the ground, separated 100m from each other, launch one rocket each vertically. The rocket explode at the same time for an observer, on the ground, that's midway between the rocket explosion. At the exact time the observer sees the rockets exploding a spaceship flies over his head, horizontally, at a speed of 0.7c. The ship length as seen by the observer is 15m.

(c)How much time goes by, to a tripulant of the spaceship, for the ship to complete the 100m between the two students?
(d)For a tripulant of the spaceship is the explosion of the rockets simultaneous? What's the time interval? (time between the first rocket explosion and the second, as seen by the tripulant)


Homework Equations



After solving the first two questions I've reached this data:
Actual size of the ship = 71.4m
Spaceship length as measured by the tripulant = 21m

As to question (c) I used the equation t=d/v to solve it.

The Attempt at a Solution



(c) I think I've done her correctly. I've simply divided the length between the two students as seen by a tripulant in a ship by her speed:
t=71.4/0.7c=3.4*10^-7

(d) I know the explosions are not simultaneous, however I have no idea how I'm supposed to measure the time interval between the two explosions... If anyone could give me some hint, or some equation that could help me i'd be grateful. I've read the whole relativity chapter of Serway's Physics for Scientists looking for something to help me without any luck.

Thanks, and a happy new year to everyone.
You wrote: "Actual size of the ship = 71.4m" This must be a typo. The "proper" length of the ship is the 21 meters, as seen by tripulant. It appears that the tripulant will see the two students as being about 71.4 meters apart. The two rocket explosions will be separated up the same amount, as seen by the crew-member.
 
SammyS said:
You wrote: "Actual size of the ship = 71.4m" This must be a typo. The "proper" length of the ship is the 21 meters, as seen by tripulant. It appears that the tripulant will see the two students as being about 71.4 meters apart. The two rocket explosions will be separated up the same amount, as seen by the crew-member.

Yes, it was a typo, thanks for bringing it to my attention :)
 

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